How can I return a JSON result to a Ajax.BeginForm
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Jak
908
Points
132
Posts
|
Hi, I am working with ajax for submission in mvc and I want to return json content, My view code as: @{
ViewBag.Title = "View1";
Layout = "~/Views/_LayoutPage1.cshtml";
}
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width" />
<title>AjaxSubmit</title>
</head>
<body>
<div>
@using (Ajax.BeginForm("AjaxSubmit2", "Default1", new AjaxOptions { LoadingElementId = "AjaxSubmitLoadingID", HttpMethod = "Post" }))
{
<div id="AjaxSubmitLoadingID"></div>
<input name="test" />
<button>Ajax submit</button>
}
</div>
</body>
</html>
How can I return a JSON result to a Ajax.BeginForm
Views:
14069
Total Answered: 1 Total Marked As Answer: 1 Posted On: 17-Sep-2015 04:15 Share: 
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Answers
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Brian
2376
Points
13
Posts
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Hi Jak, Use OnSuccess in jsonoption of Ajax.BeginForm() as: <div>
@using (Ajax.BeginForm("AjaxSubmit2", "Default1", new AjaxOptions { LoadingElementId = "AjaxSubmitLoadingID", OnSuccess="GetJsonResult()", HttpMethod = "Post" }))
{
<div id="AjaxSubmitLoadingID"></div>
<input name="test" />
<button>Ajax submit</button>
}
<script type="text/javascript">
function GetJsonResult(JSON) {
//JSON
}
</script>
</div>
And the action in the controller return json result as: [HttpPost]
public ActionResult AjaxSubmit2(AjaxlModel model)
{
return Json("simple json");
}
Posted On:
22-Sep-2015 00:18
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