We can using simple HttpResponseMessage by suing content stream to pass to content:
// using System.IO;
// using System.Net.Http;
// using System.Net.Http.Headers;
public HttpResponseMessage RecieveUserImage()
{
byte[] ImageByte = { };
HttpResponseMessage result = new HttpResponseMessage(HttpStatusCode.OK);
System.IO.MemoryStream oMemoryStream = new System.IO.MemoryStream(ImageByte);
result.Content = new StreamContent(oMemoryStream);
result.Content.Headers.ContentType = new MediaTypeHeaderValue("image/jpeg");
return result;
}
Posted On:
22-Feb-2020 06:02